Particle Scattering

Ever wondered what happens if you shoot an electron at a proton or any other type of nucleus? At the CERN for instance a lot of such experiments take place.

Prediction

According to the Roton-Model in most cases >95%, there will happen exactly: not much up to NOTHING

The electron simply flies through the grid of Quons and their entanglement structure (or Quarks/Gluons if you prefer). A Nucleus is nearly empty and the faster the electron approaches the less time the nucleus has to interact with the electron.

Speed:

• In case of a None-Hit an electron can impact the Nucleons in different ways depending on their speed, distance and mode relative to the quons.
• In case of a very rare full hit (how ever close that might be) an electron with a big momentum might hit a Quon out of it’s structure.

A Quon is not the single grid-point you see in the visualization. The Quon is a resonance of that grid-point across the center and the sphere of the nucleon. You can imagine it as circling electron-like particle it creates a resonance-channel with a diametrically paired other Quon. This rotation is what provides a nucleon its main mass/inertia.

What happens if you hit a Quon? First you will not actually hit the Quon, you will hit the electron-like sub-particle. This destroys the quons resonance-channel and will bend the grid-line-structure. The paired Quon will temporarily hold it’s resonance. The resonance grid-structure will continue to hold the paired Quon alive in rotation. The free place and resonance-channel on the opposite side will suck-in and en-weave any available electron-like particle. In the worst case it will use one of the core positrons (e-/e+) to fill the gap.

Prediction 1: Single grid-lines (reson) will eventually split-up letting the two dangling resonance potentials rotated around for some while, until they happen to align again and rejoin into the grid structure.

Prediction 2: A grid-node might be shoot out. Any nearby electron will immediately fill its place again. And if there is no electron around to fill the missing grid-node? Might loosing the central electron destabilize the Nucleus? It might loos inherent stability and eventually implode. Freeing all kinds of core constituents, or rather differently dissected resonance patterns.

Prediction 3: In some cases, a whole Quon-Pair might be hit out of the structure. A so called Pion (Quark/Anti-Quark pair). This resonance-pattern will not be stable though, as it needs the other Pions of the Nucleus to retain stability. The Pion will decay into two single rotating electrons (maybe a neutrino or myon) and eventually decay into 2 electrons. A Nucleon missing a single Quon-Pair would not be stable. So it will either fill up it’s missing bits via the existing resonances - or it will decay into smaller energy patterns.

RQM Necessity: Sub-compounds of nucleons once isolated from their rotonal interaction are not stable. They have the wrong momentum, speed, alignment to remain self-sustained. What isolated stable particles will end up from the whole Nucleus decay processes according to the RQM: neutron, proton, electron (3-Tier), neutrino (1-Tier), photon.

RQM - Quon decay

If a 4-Tier Quon is isolated, it decays into its node-point (3-Tier electron), a single remaining rotating electron-resonance-channel (1-Tier electron-Neutrino, quon-span), and a myon-neutrino (nucleus-span).

If a momentum is not matching a stable rotation a Neutrino might decay into two photons.

This at least holds, if the latest model-version might show to be accurate.

Verification: Decay process: Pions –> myon + neutrino. Myon –> Electron + Electron-Neutrino + Myon-Neutrino Final outcome: electrons/positrons + neutrinos.

More Details: Check scattering experiment results in standard physics:

• Hard electron scattering does not expose permanent sub-nucleon constituents or empty internal structures; it reveals a dynamical quark–gluon system that, if disrupted beyond binding capacity, responds by hadronizing into observable mesons and baryons rather than leaving an incomplete nucleon behind.
• Quarks are confined. Color flux tubes cannot terminate freely. If a quark is knocked out, nature will create new quark-Antiquark pairs.
• Hadronic jets: pions ($\pi^+-, \pi^0$, kaons)
• Resonances ($\delta$, $N^*$)
• Sometimes Protons, Neutrons
• Photons from $pi^0 –> \gamma \gamma$
• Never: free quarks, free gluons, a “damaged nucleon” with missing internal pieces
• A hit Nucleus must relax by: emitting hadrons, fragmenting completely, re-forming a bound baryon.

At the end the intermediate products are not stable. At the end all resolves to : electrons (e-/e+) and neutrinos and photons.

Did you realize: “Color flux tubes” that sounds like a resonance channel. And that they can not “end freely” seems familiar, at least if the core wants to keep the tube as a grid-line.

Question: Might 3 resonance-potentials pointing to the same central position “create” a Tri-Roton in the LEDO-Field? Question: How can particle/anti-particle pairs “appear” in the RQM?

Particle/Anti-Particle :If an existing resonance channel splits up, then their axis will not only loose alignment, but they will turn from anti-parallel alignment to parallel-alignment and leave into opposite directions. This results in particle/anti-particle pairs.

Simulation

Have a look at the following simulation of a scattering experiment. You can observe an electron being thrown straight through an Alpha-Particle.

Scattering experiment. Electron versus Alpha-Particle:

Structure explanations

An Alpha-Particle is a cluster built up from the parts of 2 Protons + 2 Neutrons and contains 2 e+ electrons (or positrons in this state). The blue dots are Trions or rather Quadrons (4-Tier Rotons), nut you can imagine them as specially resonance-entangled electrons. The center electrons (e+) are also drawn in blue. The grids symbolize the resonance channels (distance entanglements) and therefore force interactions. The structure is simplified and does not visualize the rotational resonances of the Quadrons forming them into a Quon (rotating grid-node with 4 resonant connections, rotating in a circle). Rotating Trions/Quadrons build up constructs named Quons. Two Quons paired across the center build Pions (Quark/Anti-Quark pairs) known from standard physics.

Simulation conditions

Have this in mind:

• The electron in the example does not hit any Reson/Trions/Quons
• The electron in the example is quiet slow, this allows for some short interactions, mostly via energy-density repulsion
• The alpha-particle is not in a completely quiescent state and shows some natural “wobbling” too.
• The vertices are drawn in green when they exactly meet the perfect resonance conditions/positions.

Result

• The electron passes through with not much persisting effect.

Experimental Verification

Electron–Proton Scattering: What Usually Happens? [Open AI]

In electron–proton scattering experiments, the vast majority of events show no dramatic interaction.

Typical outcome distribution (order of magnitude):

• $> 99%$ of electrons pass the proton with only negligible deflection
• $~0.1–1%$ show a measurable but small-angle scattering
• $≪ 0.01%$ result in large-angle scattering or inelastic excitation
• $≪≪ 0.001%$ involve hard scattering off individual quarks

Thus, in practical terms, almost all electrons “shoot through” without noticeable effect.

Why this happens:

• The proton is not a hard object but a quantum system with an extended electromagnetic field.
• Electron–proton interactions are governed by long-range Coulomb forces, not direct contact.
• The scattering cross section is strongly forward-peaked, scaling approximately as $\frac{d\sigma}{d\Omega} \propto \frac{1/\sin^4(\theta/2)}$ which makes large deflections extremely rare.

Key standard interpretation

“Passing through the proton” does not mean the proton is empty. It means that strong momentum transfer requires extremely precise conditions, which occur only in a tiny fraction of events.

Bottom line

More than 99% of electron–proton scattering events result in almost no observable interaction. The rare, highly informative events are extracted from millions to billions of ordinary pass-throughs.

Final Takeway: Do you remember what was proclaimed right at the beginning of formulating the RQM? Only resonance potentials of the same span can create resonance channels. This is the experimental verification of that claim: electrons only (strongly) interact with other electrons and not with quons or protons directly.

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